-16x^2+16x+850=0

Solution for -16x^2+16x+850=0 equation:

-16x^2+16x+850=0

a = -16; b = 16; c = +850;
Δ = b2-4ac
Δ = 162-4·(-16)·850
Δ = 54656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{54656}=\sqrt{64*854}=\sqrt{64}*\sqrt{854}=8\sqrt{854}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{854}}{2*-16}=\frac{-16-8\sqrt{854}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{854}}{2*-16}=\frac{-16+8\sqrt{854}}{-32}
$